question_answer

For vaporisation of water at 1 atm pressure, the values of \[\Delta H\] and \[\Delta S\] are \[40.63\,kJ\,mo{{l}^{-1}}\] and \[108.8\,J{{K}^{-1}}\,mo{{l}^{-1}}\], respectively. The temperature when Gibbs energy change \[(\Delta G)\] for this transformation will be zero, is                                                                        [AIPMT (M) 2010]

A)  273.4 K      

B)  393.4 K           

C)  373.4 K              

D)       293.4 K

Correct Answer: C

Solution :

(given)