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NEET Chemistry NEET PYQ-The Solid State

  • question_answer
    The ionic radii of \[{{A}^{+}}\] and \[{{B}^{-}}\] ions are \[0.98\times {{10}^{-10}}m\] and \[1.81\times {{10}^{10}}\text{ }m\]. The coordination number of each ion in AB is :-      [NEET - 2016]

    A)       6

    B) 4

    C) 8

    D) 2

    Correct Answer: A

    Solution :

    [a] \[\text{radio ratio = }\frac{{{r}_{+}}}{{{r}_{-}}}=\frac{0.98\times {{10}^{-10}}}{1.81\times {{10}^{-10}}}=0.54\]radii ratio is in between 0.414 to 0.732 so, coordination number is 6


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