A) \[50mL\text{ }of\text{ }2M\text{ }AgN{{O}_{3}}+50mL\text{ }of\text{ }1.5M\text{ }KI\]
B) \[50mL\text{ }of\text{ }0.1M\text{ }AgN{{O}_{3}}+50mL\text{ }of\text{ }0.1M\text{ }KI\]
C) \[50mL\text{ }of\text{ }1M\text{ }AgN{{O}_{3}}+50mL\text{ }of\text{ }1.5M\text{ }KI\]
D) \[50mL\text{ }of\text{ }M\text{ }AgN{{O}_{3}}+50mL\text{ }of\text{ }2M\text{ }KI\]
Correct Answer: C , D
Solution :
[c, d] \[AgN{{O}_{3}}+KI\to AgI+KN{{O}_{3}}\] |
for \[{{[AgI]}^{I}}\]colloidal |
KI must be in excels |
, both correct |
50 me\[~AgN{{O}_{3}}+50\] me |
1.5 m |
KI |
50 ml \[~AgN{{O}_{3}}+50\] ml |
2 m KI |
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