A) Acceleration \[=-{{k}_{0}}x+{{k}_{1}}{{x}^{2}}\]
B) Acceleration \[=-\,k\,(x+a)\]
C) Acceleration \[=\,k\,(x+a)\]
D) Acceleration \[=kx\] where \[k,\,{{k}_{0}},\,{{k}_{1}}\] and a are all positive.
Correct Answer: B
Solution :
Key Idea Acceleration \[\propto -\](displacement). |
\[A\,\propto -y\] |
\[A=-{{\omega }^{2}}y\] |
\[A=-\frac{k}{m}y\] |
\[A=-ky\] |
Here, \[y=x+a\] |
\[\therefore \] acceleration \[=-k(x+a)\] |
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