| Two particles of mass 5 kg and 10 kg respectively are attached to the two ends of a rigid rod of length 1 m with negligible mass. |
| The centre of mass of the system from the 5 kg particle is nearly at a distance of: [NEET 2020] |
A) 50 cm
B) 67 cm
C) 80 cm
D) 33 cm
Correct Answer: B
Solution :
| [b] |
 |
| \[{{X}_{cm}}=\frac{{{m}_{1}}{{x}_{1}}+{{m}_{2}}{{x}_{2}}}{{{m}_{1}}+{{m}_{2}}}\] |
| \[=\frac{5\times 0+100\times 10}{5+10}=\frac{200}{3}=66.66\,\,cm\] |
| \[{{X}_{cm}}\simeq 67\,\,cm\] |
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