NEET Physics Rotational Motion NEET PYQ-Rotational Motion

  • question_answer
    A disc of radius 2 m and mass 100 kg rolls on a horizontal floor. Its centre of mass has speed of 20 cm/s. How much work is needed to stop it? [NEET 2019]

    A) 2 J

    B) 1 J

    C) 3 J

    D) 30 kJ

    Correct Answer: C

    Solution :

    [c] \[w=\frac{1}{2}m{{V}^{2}}\left( 1+\frac{{{K}^{2}}}{{{r}^{2}}} \right)\]
                \[=\frac{1}{2}\times 100{{(20\times {{10}^{-2}})}^{2}}\left( 1+\frac{1}{2} \right)\]
                \[=\frac{4}{3}\times \frac{3}{2}=3J\]


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