A) 25 N
B) 50 N
C) 78.5 N
D) 157 N
Correct Answer: D
Solution :
\[\Rightarrow \] \[m=50kg\Rightarrow r=0.5\Rightarrow \alpha =2rev/{{s}^{2}}\] |
\[\Rightarrow \] Torque produce by the tension in the string |
\[=T\times R=T\times 0.5=\frac{T}{2}Nm\] ...(i) |
We know \[\tau =/\alpha \] (ii) |
From Eqs. (i) and (ii), |
\[=\left( \frac{M{{R}^{2}}}{2} \right)\times (2\times 2\pi )\frac{rad}{{{s}^{2}}}\] |
\[\therefore \] \[{{l}_{\text{solid cylinder}}}\,=\frac{M{{R}^{2}}}{2}\] |
\[\frac{T}{2}=\frac{50\times {{(0.5)}^{2}}}{2}\times 4\pi \] |
\[T=50\times \frac{1}{4}\times 4\pi \] |
\[=50\pi =157N\] |
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