NEET Physics Motion in a Straight Line / सरल रेखा में गति NEET PYQ-One Dimensional Motion

  • question_answer
    Preeti reached the metro station and found that the escalator was not working. She walked up the stationary escalator in time \[{{t}_{1}}\]. On other days, if she remains stationary on the moving escalator, then the escalator takes her up in time \[{{t}_{2}}\]. The time taken by her to walk up on the moving escalator will be                                 [NEET-2017]

    A) \[{{t}_{1}}-{{t}_{2}}\]

    B) \[\frac{{{t}_{1}}+{{t}_{2}}}{2}\]

    C) \[\frac{{{t}_{1}}{{t}_{2}}}{{{t}_{2}}-{{t}_{1}}}\]

    D) \[\frac{{{t}_{1}}{{t}_{2}}}{{{t}_{2}}+{{t}_{1}}}\]

    Correct Answer: D

    Solution :

    [d] Velocity of girl w.r.t. elevator \[=\frac{d}{{{t}_{1}}}={{v}_{ge}}\]
    Velocity of elevator w.r.t. ground \[{{v}_{eG}}=\frac{d}{{{t}_{2}}}\] then velocity of girl w.r.t. ground
    \[\vec{v}{{=}_{gG}}={{\vec{v}}_{ge}}+{{\vec{v}}_{eG}}\]
    i.e.,       \[{{v}_{gG}}={{v}_{ge}}+{{v}_{eG}}\]
                \[\frac{d}{t}=\frac{d}{{{t}_{1}}}+\frac{d}{{{t}_{2}}}\]
                \[\frac{1}{t}=\frac{1}{{{t}_{1}}}+\frac{1}{{{t}_{2}}}\]
                \[t=\frac{{{t}_{1}}{{t}_{2}}}{({{t}_{1}}+{{t}_{2}})}\]


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