A) 25.8 MeV
B) 23.6 MeV
C) 19.2 MeV
D) 30.2 MeV
Correct Answer: B
Solution :
The reaction can be written as: |
\[_{1}{{H}^{2}}+{{\,}_{1}}{{H}^{2}}\,\xrightarrow[{}]{{}}\,{{\,}_{2}}H{{e}^{4}}\,+\text{energy}\] |
The energy released in the reaction in difference of binding energies of daughter and parent nuclei. |
Hence, energy released |
= binding energy of \[_{2}H{{e}^{4}}\] |
\[=28-2\times 2.2=23.6\,MeV\] |
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