A) 3-neutrons
B) 2-neutrons
C) \[\alpha \]-particle
D) \[\beta \]-particle
Correct Answer: A
Solution :
[a] \[_{92}{{U}^{235}}\,\] nucleus absorbs a neutron and then disintegrate in \[_{54}X{{e}^{139}}\,,{{\,}_{38}}S{{r}^{94}}\] and X. |
Thus \[_{92}{{U}^{235}}+{{\,}_{0}}{{n}^{1}}\,\xrightarrow[{}]{{}}{{\,}_{54}}X{{e}^{139}}\,+{{\,}_{38}}S{{r}^{94}}+\underset{'X'}{\mathop{3,{{\,}_{0}}{{n}^{1}}}}\,\] |
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