NEET Chemistry NEET PYQ-Nuclear Chemistry

  • question_answer
    If \[_{b}^{a}X\] species emit firstly a positron, then two \[\alpha \] and two \[\beta \] and in last one a is also emitted and finally convert in \[_{d}^{c}Y\] species so correct relation is: [AIPMT 2001]

    A)             \[a=c+12,\text{ }d=b5\]

    B) \[a=c-8,\text{ }d=b-1\]

    C) \[a=c-6,\text{ }d=b-0\]

    D) \[~a=c-4,\text{ }a=b-2\]

    Correct Answer: A

    Solution :

    [a]
                Hence, \[d=b-5,\,c=a-12\]
                or         \[a=c+12\,\,b=d+5\]
                            \[d=b-5\]


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