A) \[a=c+12,\text{ }d=b5\]
B) \[a=c-8,\text{ }d=b-1\]
C) \[a=c-6,\text{ }d=b-0\]
D) \[~a=c-4,\text{ }a=b-2\]
Correct Answer: A
Solution :
[a] |
Hence, \[d=b-5,\,c=a-12\] |
or \[a=c+12\,\,b=d+5\] |
\[d=b-5\] |
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