| A human body required the 0.01 M activity of radioactive substance after 24 hour. |
| Half-life of radioactive is 6 hour. Then injection of maximum activity of radioactive substance that can be injected: [AIPMT 2001] |
A) 0.08
B) 0.04
C) 0.16
D) 0.32
Correct Answer: C
Solution :
| [c] Remaining activity = 0.01 M after 24 hrs Remaining activity |
| = Initial activity \[\times {{\left( \frac{1}{2} \right)}^{n}}\] |
| Used half life time (n) |
| \[=\frac{\text{Total}\,\text{time}}{{{T}_{1/2}}}=\frac{24}{6}=4\] |
| So 0.01 = Initial activity \[\times {{\left( \frac{1}{2} \right)}^{4}}\] |
| Initial activity \[=0.0116=0.16\] |
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