A) 4.68 g
B) 2.34 g
C) 1.17 g
D) 9.36 g
Correct Answer: A
Solution :
[a] Given |
Half-life \[({{t}_{1/2}})=3\text{ }h\] |
Initial mass \[({{N}_{0}})=300\,g\] |
Total time \[(T)=18\text{ }h\] |
Mass left \[(N)=?\] |
We know that, \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{n}}\] |
where n = number of half life |
\[n=\frac{Total\,time}{Half-life}=\frac{18}{3}=6\] |
So, \[\frac{N}{300}={{\left( \frac{1}{2} \right)}^{6}}\] |
or \[\frac{N}{300}=\frac{1}{64}\] |
\[N=\frac{300}{64}=4.68\,g\] |
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