A) 0.3 N
B) 3 N
C) 30 N
D) 300 N
Correct Answer: C
Solution :
Key Idea: The force imparted (or impulse) by the ball to the hands of the player is equal to the rate of change of linear momentum. |
Force imparted = Rate of change of momentum |
or \[F=\frac{\Delta p}{\Delta t}\] |
or \[F=\frac{{{p}_{1}}-{{p}_{2}}}{\Delta t}\] |
or \[F=\frac{m({{v}_{1}}-{{v}_{2}})}{\Delta t}\] |
Here, |
\[m=150\text{ }g=0.150\text{ }kg,\text{ }{{v}_{1}}=20\text{ }m/s,\text{ }{{v}_{2}}=0\] |
\[\Delta t=0.1\,\,s\] |
\[\therefore \] \[F=\frac{0.150\times (20-0)}{0.1}=30\,N\] |
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