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NEET Physics Magnetic Effects of Current / करंट का चुंबकीय प्रभाव NEET PYQ-Magnetic Effects Of Current

  • question_answer
    A proton carrying 1 MeV kinetic energy is moving in a circular path of radius R in uniform magnetic field. What should be the energy of an \[\alpha -\]article to describe a circle of same radius in the same field?                              [AIPMT (M) 2012]

    A)  2 MeV          

    B)       1 MeV 

    C)  0.5 MeV          

    D)       4 MeV

    Correct Answer: B

    Solution :

    [b] For proton
    \[r=\frac{\sqrt{2m(KE)}}{qB}\]
                So        \[q\propto \sqrt{m(KE)}\]
    Hence    \[\frac{e}{2e}=\sqrt{\frac{({{m}_{p}})(1MeV)}{(4{{m}_{p}})(KE)}}\]
                \[\frac{1}{4}=\frac{1MeV}{4KE}\]
                            \[KE=1\,MeV\]


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