A) inside the pipe only
B) outside the pipe only
C) both inside and outside the pipe
D) no where
Correct Answer: B
Solution :
| [b] According to Ampere's circuital law |
| \[B\,(2\pi r)={{\mu }_{0}}\times 0\] |
| or \[B=0\] |
| So, inside a hollow metallic (copper) pipe carrying current, the magnetic field is zero. But for external points, the whole current behaves as if it were concentrated at the axis only, so outside |
| \[{{B}_{0}}=\frac{{{\mu }_{0}}i}{2\pi r}\] |
| Thus, the magnetic field is produced outside the pipe only. |
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