question_answer

pH of a saturated solution of \[Ba{{(OH)}_{2}}\] is 12. The value of solubility product K of \[Ba{{(OH)}_{2}}\] is                                                                                                                                     [AIPMT (S) 2012]

A)  \[3.3\times {{10}^{-7}}\]        

B)       \[5.0\times {{10}^{-7}}\]

C)  \[4.0\times {{10}^{-6}}\]        

D)       \[5.0\times {{10}^{-6}}\]

Correct Answer: B

Solution :

Given, of

We know that,

dissolves in water as