A) 11 \[\sigma \] bonds and 2 \[\pi \] bonds
B)
13 \[\sigma \] bonds and no 
bond
C)
10 
bonds and 3 bonds
D)
8 bonds and 5 bonds
Correct Answer: C
Solution :
[c] \[HC\equiv CCH=CHC{{H}_{3}}\]| \[10\sigma +3\pi -Bonds\] |
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