A) 1.70
B) 2.35
C) 3.0
D) 1.50
Correct Answer: A
Solution :
| Given, pressure \[=150\text{ }mm\] of Hg |
| Pumping rate of heart of a man |
| \[=\frac{dV}{dt}=\frac{5\times {{10}^{-3}}}{60}{{m}^{3}}/s\] |
| Power of heart, \[=P.\frac{dV}{dt}=\rho gh.\frac{dV}{dt}[p=\rho gh]\] |
| \[\Rightarrow \] \[\frac{(1.36\times {{10}^{3}}kg/{{m}^{3}})(10)\times 0.15\times 5\times {{10}^{-3}})}{60}\] |
| \[=1.70\,W\] |
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