NEET Chemistry NEET PYQ-Electrochemistry

The equivalent conductances of \[B{{a}^{2+}}\] and \[C{{l}^{-}}\] are 127 and 76 \[oh{{m}^{-1}}\,\,c{{m}^{-1}}\,e{{q}^{-1}}\] respectively at infinite dilution. The equivalent conductance of \[BaC{{l}_{2}}\] at infinite dilution will be: [AIPMT 2000]

A) 139.5

B) 203

C) 279

D) 101.5

Correct Answer: A

Solution :

[a] The equivalent conductance of \[BaC{{l}_{2}}\] at infinite dilution

\[{{\lambda }_{\infty }}\] of \[BaC{{l}_{2}}=\frac{1}{2}{{\lambda }_{\infty }}\] of \[B{{a}^{2+}}+{{\lambda }_{\infty }}\] of \[C{{l}^{-}}\]

\[=\frac{127}{2}+76=139.5\]