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NEET Chemistry NEET PYQ-Electrochemistry

  • question_answer
    Which of the following expressions correctly represents the equivalent conductance at infinite dilution of \[A{{l}_{2}}{{(S{{O}_{4}})}_{3}}\]. Given that \[\Lambda {{_{Al}^{o}}^{3+}}\] and \[\Lambda _{SO_{4}^{2-}}^{o}\]  are the equivalent conductance’s at infinite dilution of the respective ions?   [AIPMT (M) 2010]

    A) \[2{{\Lambda }^{o}}_{A{{l}^{3+}}}+3{{\Lambda }^{o}}_{so\frac{2-}{4}}\]

    B) \[{{\Lambda }^{o}}_{A{{l}^{3+}}}+{{\Lambda }^{o}}_{so\frac{2-}{4}}\]

    C) \[({{\Lambda }^{o}}_{A{{l}^{3+}}}+3{{\Lambda }^{o}}_{so\frac{2-}{4}})\times 6\]

    D) \[\frac{1}{3}{{\Lambda }^{o}}_{A{{l}^{3+}}}+\frac{1}{2}{{\Lambda }^{o}}_{so\frac{2-}{4}}\]

    Correct Answer: A

    Solution :

    [a] \[A{{l}_{2}}{{(S{{O}_{4}})}_{3}}2A{{l}^{3+}}+3SO_{4}^{2-}\]. Since equivalent conductance’s are given only for ions, the equivalent conductance at infinite dilution, \[\Lambda _{eq}^{\infty }=\Lambda _{Al\,3+}^{o}+\Lambda _{so_{4}^{2-}}^{o}\]


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