A) \[1.25\times {{10}^{-5}}\]
B) \[1.25\times {{10}^{-6}}\]
C) \[6.25\times {{10}^{-4}}\]
D) \[1.25\times {{10}^{-4}}\]
Correct Answer: A
Solution :
| [a] Degree of dissociation, \[\alpha =\frac{{{\Lambda }^{c}}}{{{\Lambda }^{\infty }}}\] where,\[{{\Lambda }^{c}}\] and \[{{\Lambda }^{\infty }}\] are equivalent conductances at a given concentration and at infinite dilution respectively. |
| \[0.5\times {{10}^{-3}}{{s}^{-1}}\]\[0.0\times {{10}^{-2}}{{s}^{-1}}\] |
| From Ostwald's dilution law (for weak monobasic acid)\[Phenol\xrightarrow[{}]{Zn\,dust}X\xrightarrow[Anhydrous\,AlC{{l}_{3}}]{C{{H}_{3}}Cl}Y\xrightarrow[{}]{\begin{smallmatrix} Alkaline \\ KMn{{O}_{4}} \end{smallmatrix}}Z,\]or\[A+B\to \]\[=k{{[A]}^{2}}[B]\]\[=k[A]{{[B]}^{2}}\]or\[=k{{[A]}^{2}}{{[B]}^{2}}\] |
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