A) 2.5 H
B) 2.0 H
C) 1.0 H
D) 4.0 H
Correct Answer: C
Solution :
| Key Idea: Inductance of a coil is numerically equal to the emf induced in the coil when the current in the coil changes at the rate of \[1A{{s}^{-1}}\]. |
| If \[I\] is the current flowing in the circuit, then flux linked with the circuit is observed to be proportional to I, i.e., \[\phi \propto I\] or \[\phi =LI\] ...(i) |
| where L is called the self-inductance or coefficient of self-inductance or simply inductance of the coil. |
| Net flux through solenoid, |
| \[\phi =500\times 4\times {{10}^{-3}}=2Wb\] |
| or \[2=L\times 2\] |
| [after putting values in Eq. (i)] or \[L=1H\] |
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