A) fifth group
B) fifteenth group
C) second group
D) third group
Correct Answer: A
Solution :
| An atom has electronic configuration |
| \[1{{s}^{2}},\,2{{s}^{2}}\,2{{p}^{6}},\,3{{s}^{2}}\,3{{p}^{6}}3{{d}^{3}},\,4{{s}^{2}}\] |
| It is a member of d-block element because the last electron is filled in d-subshell as \[3{{d}^{3}}\] and the following electronic configuration is possible for d-subshellas \[(n-1)\] d-subshellas \[(n-1)\,{{d}^{10\,\text{to}\,10}}\] |
| \[\begin{matrix} Gruop\text{ }No.\text{ }III & B & IVB & VB & VIB & VIIB & VIII & VIII & VIII & IB & IIB \\ {} & (13) & (14) & (15) & (16) & (17) & (18) & (19) & (20) & (21) & (22) \\ n{{s}^{2}}(n-1)\,{{s}^{2}}{{p}^{6}} & {{d}^{1}} & {{d}^{2}} & {{d}^{3}} & {{d}^{4}} & {{d}^{5}} & {{d}^{6}} & {{d}^{7}} & {{d}^{8}} & {{d}^{9}} & {{d}^{10}} \\ \end{matrix}\] |
| Hence, it is member of fifth group. |
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