A) 8.29, 9.32
B) 9.32, 9.32
C) 8.29, 8.29
D) 9.32, 8.29
Correct Answer: D
Solution :
| First ionisation potential of Be(completely filled orbital) is greater than boron due to stable configuration \[_{4}Be\text{ }=\text{ }1{{s}^{2}},\text{ }2{{s}^{2}}\] |
| \[_{5}B\text{ }=\text{ }1{{s}^{2}},\text{ }2{{s}^{2}}2{{p}^{1}}\] |
| Order of attraction of electrons towards nucleus \[2s>2p,\] so more amount of energy is required to remove the electron with 2s-orbital in comparison to 2 porbital. So ionization potential of Be is 9.32 eV and B is 8.29 eV. |
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