A) \[L{{i}_{2}}\]
B) \[{{C}_{2}}\]
C) \[{{O}_{2}}\]
D) \[H{{e}_{2}}\]
Correct Answer: D
Solution :
| [d] For \[H{{e}_{2}}\] molecule |
| Electronic configuration is \[\sigma 1{{s}^{2}},\,\,{{\sigma }^{*}}1{{s}^{2}}\] |
| so bond order \[=\frac{1}{2}[{{N}_{b}}-{{N}_{a}}]\] |
| \[=\frac{1}{2}[2-2]\] |
| \[=0\] |
| Since, bond order is zero, so \[H{{e}_{2}}\] molecule does not exist. |
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