question_answer

\[{{H}_{2}}O\] is dipolar, whereas \[Be{{F}_{2}}\] is not. It is because:                      [AIPMT (S) 2004]

A)  the electro negativity of F is greater than that of O

B)  \[{{H}_{2}}O\] involves hydrogen bonding whereas\[Be{{F}_{2}}\]  is a discrete molecule

C)  \[{{H}_{2}}O\]is linear and \[Be{{F}_{2}}\] is angular

D)   \[{{H}_{2}}O\] is angular and \[Be{{F}_{2}}\] is linear

Correct Answer: D

Solution :

The structure of \[{{H}_{2}}O\] is angular V-shape and as\[s{{p}^{3}}\]-hybridisation and bond angle is\[105{}^\circ \]. Its dipole moment value is positive or more than zero.

but in \[Be{{F}_{2}}\], structure is linear due to sp-hybridization\[(\mu =0)\]

Thus, due to \[\mu >0,\,{{H}_{2}}O\]is dipolar and due to\[\mu =0,\]\[Be{{F}_{2}}\] is non-polar.