A) -121 kJ per mol
B) +121 kJ per mol
C) +242 kJ per mol
D) -242 kJ per mol
Correct Answer: A
Solution :
[a] |
\[\Delta H=\] [\[\Delta H\]of combustion of cyclohexane |
- (\[\Delta H\] of combustion of cyclohexene |
+\[\Delta H\]of combustion of H2)] |
\[=-[-3920-(3800-24)]\,kJ\] |
\[=-[3920+4041]\,kJ\] |
= -[121] kJ |
= -121 kJ |
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