A) \[S{{n}^{4+}}\] is reducing while \[P{{b}^{4+}}\] is oxidizing
B) \[S{{n}^{2+}}\] is reducing while \[P{{b}^{4+}}\] is oxidizing
C) \[S{{n}^{2+}}\] is oxidising while \[P{{b}^{4+}}\] is reducing
D) \[S{{n}^{2+}}\] and \[P{{b}^{2+}}\] are both oxidising and reducing
Correct Answer: A
Solution :
[a] Inability of electrons of the valence shell to participate in bonding on moving down the group in heavier p-block elements is called inert pair effect As a result, Pb(ll) is more stable than Pb(IV) Sn(IV) is more stable than Sn(ll) Pb(IV) is easily reduced to Pb(ll) Pb(IV) is oxidising agent Sn (ll) is easily oxidised to Sn(IV) Sn (ll) is reducing agentYou need to login to perform this action.
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