A) \[A{{l}_{2}}{{O}_{3}}+HF+NaAl{{F}_{4}}\]
B) \[A{{l}_{2}}{{O}_{3}}+Ca{{F}_{2}}+NaAl{{F}_{4}}\]
C) \[A{{l}_{2}}{{O}_{3}}+N{{a}_{3}}Al{{F}_{6}}+Ca{{F}_{2}}\]
D) \[A{{l}_{2}}{{O}_{3}}+KF+N{{a}_{3}}Al{{F}_{6}}\]
Correct Answer: C
Solution :
[c] Alumina, , is a bad conductor of electricity and has very high melting point, so before subjecting to electrolysis, it is mixed with fluorspar () and cryolite (), which lower its melting point and make it more conducting.You need to login to perform this action.
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