MGIMS WARDHA MGIMS WARDHA Solved Paper-2015

  • question_answer
    \[n\]balls each of mass m impinge elastically each second on a surface with velocity v. The average force experienced by the surface will be

    A)  \[2nmv\]  

    B)  \[nmv\]   

    C)  \[\frac{nmv}{2}\]                           

    D)  \[4nmv\]

    Correct Answer: A

    Solution :

                    Change in momentum of each ball\[=mv-(-mv)\] \[=2mv\] Time taken = 1 s So, \[{{F}_{av}}=\frac{total\text{ }change\text{ }in\text{ }momentum}{time\text{ }taken}\]                 \[=n\frac{2mv}{1}=2nmv\]


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