MGIMS WARDHA MGIMS WARDHA Solved Paper-2015

  • question_answer
    Mass of 1 mol of air is\[29\times {{10}^{-3}}kg\]. The speed of sound at STP will be nearly

    A)  3325m/s             

    B)  340 m/s

    C)  320 m/s              

    D)  325 m/s

    Correct Answer: A

    Solution :

                    At STP, \[p=1atm=1.01\times {{10}^{5}}N/{{m}^{2}}\] Density of air\[\rho =\frac{mass\,of\,1\,mol\,of\,air\,(in\,kg)}{volume\,of\,1\,mol(in\,{{m}^{3}})}\] \[=\frac{29\times {{10}^{-3}}}{22.4\times {{10}^{-3}}}=129\,kg-{{m}^{-3}}\] From Laplace corrected formula, the velocity of sound is given by                 \[v=\sqrt{\frac{\gamma p}{\rho }}\] For air,          \[\gamma =1.41\] So, \[v=\sqrt{\frac{141\times 101\times {{10}^{5}}}{129}}=3325\,m/s\]


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