A) \[{{B}_{2}}{{H}_{6}}.N{{H}_{3}}\]
B) borazole
C) \[{{B}_{2}}{{H}_{6}}.3N{{H}_{3}}\]
D) \[{{[B{{H}_{2}}{{(N{{H}_{3}})}_{2}}]}^{+}}{{[B{{H}_{4}}]}^{-}}\]
Correct Answer: D
Solution :
Reaction of dourine with ammonia initially gives an addition product, which when heated to\[200{}^\circ C\]decomposes to give a volatile compound borazine or borazole. \[3{{B}_{2}}{{H}_{6}}+6N{{H}_{3}}\xrightarrow[{}]{{}}3{{[B{{H}_{2}}{{(N{{H}_{3}})}_{2}}]}^{+}}{{[B{{H}_{4}}]}^{-}}\] \[\xrightarrow[{}]{200{}^\circ C}\underset{Borazole}{\mathop{2{{B}_{3}}{{N}_{3}}{{H}_{6}}}}\,+2{{H}_{2}}\]
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