A) 9.315 MeV
B) 931.5 MeV
C) 83.0 MeV
D) 8.38 MeV
Correct Answer: A
Solution :
\[\Delta m=0.090\text{ }u\] Number of nucleons\[=9\] \[\therefore \]Binding energy per nucleon \[=\frac{total\text{ }binding\text{ }energy}{number\text{ }of\text{ }nucleon}\] \[=\frac{\Delta m\times 931.5}{number\text{ }of\text{ }nucleon}\] \[=\frac{0.090\times 931.5}{9}=9.315\,MeV\]
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