MGIMS WARDHA MGIMS WARDHA Solved Paper-2011

  • question_answer
    1 mole of\[{{H}_{2}}S{{O}_{4}}\]is mixed with 2 moles of\[NaOH\]. The heat evolved will be

    A)  57.3 kJ

    B)  \[2\times 57.3\text{ }kJ\]

    C)  57.3/2 kJ

    D)  Cannot be predicted

    Correct Answer: B

    Solution :

                     1 mole of\[{{H}_{2}}S{{O}_{4}}=2\]g-equivalent of\[{{H}_{2}}S{{O}_{4}}\]Hence, when 1 mole of\[{{H}_{2}}S{{O}_{4}}\]is mixed with 2 moles of\[NaOH,\]the heat evolved will be\[2\times \]\[57.3\text{ }kJ\].


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