MGIMS WARDHA MGIMS WARDHA Solved Paper-2011

  • question_answer
    If a body travels half the distance with velocity \[{{v}_{1}}\] and the next half with velocity \[{{v}_{2}}\]its average velocity will be given by

    A) \[v=\sqrt{{{v}_{1}}{{v}_{2}}}\]                   

    B) \[v=\frac{{{v}_{1}}+{{v}_{1}}}{2}\]

    C)  \[v=\frac{{{v}_{1}}}{{{v}_{2}}}\]                                               

    D) \[\frac{2}{v}=\frac{1}{{{v}_{1}}}+\frac{1}{{{v}_{2}}}\]

    Correct Answer: D

    Solution :

                     Average velocity \[=\frac{total\text{ }distance\text{ }travelled}{total\text{ }time\text{ }taken}\] Let the total distance\[=d\]. \[\therefore \] \[v=\frac{d}{\frac{d}{2{{v}_{1}}}+\frac{d}{{{v}_{2}}}}\]                 \[v=\frac{d}{\frac{d}{2}\left( \frac{1}{{{v}_{1}}}+\frac{1}{{{v}_{2}}} \right)}\] Or           \[v=\frac{2{{v}_{1}}{{v}_{2}}}{{{v}_{1}}+{{v}_{2}}}\] Or           \[\frac{{{v}_{1}}+{{v}_{2}}}{{{v}_{1}}{{v}_{2}}}=\frac{2}{v}\] Or           \[\frac{1}{{{v}_{1}}}+\frac{1}{{{v}_{2}}}=\frac{2}{v}\]  


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