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MGIMS WARDHA MGIMS WARDHA Solved Paper-2011

  • question_answer
    The temperature at which root mean square velocity of molecules of helium is equal to root mean square velocity of hydrogen at NTP is

    A)  273°C                                   

    B)  273 K

    C)   546°C                                  

    D)   844 K

    Correct Answer: A

    Solution :

                     \[{{v}_{rms}}=\sqrt{\frac{3RT}{M}}\]rms velocity of He and\[{{H}_{2}}\]is same. i.e.,        \[\frac{{{T}_{{{H}_{2}}}}}{{{M}_{{{H}_{2}}}}}=\frac{{{T}_{He}}}{{{M}_{He}}}\] or            \[\frac{273}{2}=\frac{{{T}_{He}}}{4}\] or            \[\frac{273}{2}=\frac{{{T}_{He}}}{4}\] \[=546-273\] \[=273{}^\circ C\]


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