A) 30rad/s2
B) 1880 degree/s2
C) 40 rad/s2
D) 1980 degree/s2
Correct Answer: D
Solution :
Given,\[{{h}_{1}}=1200\text{ }cycle/\min =20\text{ }cycle/s\] \[{{n}_{2}}=\frac{4500}{60}cycle/s=75cycle/s\] Angular acceleration \[\alpha =\frac{{{\omega }_{2}}-{{\omega }_{1}}}{t}\] \[=\frac{2\pi ({{n}_{2}}-{{n}_{1}})}{t}\] \[=\frac{2\times 180(75-20)}{10}\] \[=1980\,\deg ree/{{s}^{2}}\]
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