A) \[C{{H}_{3}}OH\]
B) \[C{{H}_{3}}\overset{+}{\mathop{N}}\,{{H}_{3}}\]
C) \[C{{H}_{2}}NH_{2}^{+}\]
D) \[C{{H}_{3}}\overset{-}{\mathop{N}}\,H\]
Correct Answer: B
Solution :
Conjugate acid is obtained, when a base accepts a proton. \[\underset{base}{\mathop{C{{H}_{3}}N{{H}_{2}}}}\,+\underset{proton}{\mathop{{{H}^{+}}}}\,\xrightarrow{{}}\underset{conjugate\text{ }acid}{\mathop{C{{H}_{3}}NH_{3}^{+}}}\,\]
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