A) \[\frac{L}{4}\]
B) \[2L\]
C) \[4L\]
D) \[\frac{L}{2}\]
Correct Answer: A
Solution :
Angular momentum \[L=I\omega \] ...(i) Kinetic energy \[K=\frac{1}{2}I{{\omega }^{2}}=\frac{1}{2}L\omega \] [from Eq. (i)] \[\therefore \] \[L=\frac{2K}{\omega }\] Now, \[L=\frac{2\left( \frac{K}{2} \right)}{2\omega }\] \[\Rightarrow \] \[L'=\frac{L}{4}\]
You need to login to perform this action.
You will be redirected in
3 sec
