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MGIMS WARDHA MGIMS WARDHA Solved Paper-2010

  • question_answer
    \[_{92}{{U}^{238}}\]on absorbing a neutron goes over to \[_{92}{{U}^{239}}.\] This nucleus emits an electron to go over to neptunium which on further emitting an electron goes over to plutonium. The resulting plutonium can be expressed as

    A) \[_{94}P{{u}^{239}}\]                                    

    B)  \[_{90}P{{u}^{219}}\]

    C) \[{{~}_{93}}P{{u}^{240}}\]                                           

    D)  \[_{92}P{{u}^{240}}\]

    Correct Answer: A

    Solution :

                     The reaction can be shown as \[_{92}{{U}^{238}}{{+}_{0}}{{n}^{1}}{{\xrightarrow{{}}}_{92}}{{U}^{239}}\xrightarrow{{}}\]                                 \[_{93}N{{e}^{239}}{{\xrightarrow{{}}}_{94}}P{{u}^{239}}{{+}_{-1}}{{e}^{0}}\]


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