A) \[CHC{{l}_{2}}COOH<C{{H}_{2}}ClCOOH<C{{H}_{3}}COOH\]
B) \[C{{H}_{3}}COOH<CHC{{l}_{2}}COOH<C{{H}_{2}}ClCOOH\]
C) \[C{{H}_{2}}BrCOOH<C{{H}_{2}}ClCOOH<C{{H}_{2}}ClCOOH\]
D) \[C{{H}_{2}}BrCOOH<C{{H}_{2}}ClCOOH<CHC{{l}_{2}}COOH\]
Correct Answer: D
Solution :
The acidity of halogen acids depends upon the number, nature and position of halogen atom. Greater the electron withdrawing influence of halogen atom, stronger will be the acid. Moreover, with increase in number of halogen atoms acidic strength also increases. Thus, the increasing order of acidity is \[C{{H}_{2}}BrCOOH<C{{H}_{2}}ClCOOH<CHC{{l}_{2}}COOH\]
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