A) 132 g
B) 44 g
C) 176 g
D) 88 g
Correct Answer: C
Solution :
\[\underset{\begin{smallmatrix} 1\text{ }mole \\ =46g \end{smallmatrix}}{\mathop{{{C}_{2}}{{H}_{5}}OH}}\,+3{{O}_{2}}\xrightarrow{{}}\underset{\begin{smallmatrix} 2\text{ }moles \\ 88g \end{smallmatrix}}{\mathop{2C{{O}_{2}}}}\,+3{{H}_{2}}O\] 1 mole (46 g)\[{{C}_{2}}{{H}_{5}}OH\]gives\[=88\text{ }g\text{ }C{{O}_{2}}\] 2 moles (92 g)\[{{C}_{2}}{{H}_{5}}OH\]will give\[=176\text{ }g\text{ }C{{O}_{2}}\]
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