In the above sequence, II is
A) \[\text{ }\!\!\beta\!\!\text{ -}\]alanine
B) \[\alpha \text{-}\]alanine
C) ethylene diamine
D) \[\text{ }\!\!\gamma\!\!\text{ -}\]amino butyric acid
Correct Answer: A
Solution :
\[\xrightarrow{B{{r}_{2}}/KOH}\underset{\begin{smallmatrix} C{{H}_{2}}COOH \\ \beta -alanine \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(II) \end{smallmatrix}}{\overset{C{{H}_{2}}N{{H}_{2}}}{\mathop{|}}}\,\]
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