A) \[1\alpha \]emission
B) \[1\beta \]emission
C) \[1\alpha \]and\[1\beta \]emission
D) \[2\alpha \]and\[1\beta \]emission
Correct Answer: B
Solution :
\[_{n}^{m}X\xrightarrow{-\beta }_{n+1}^{m}X\] The atoms of different elements having different atomic number but same mass number are called isobars. So, by emission of one \[\beta \]particle isobar is obtained.
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