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MGIMS WARDHA MGIMS WARDHA Solved Paper-2009

  • question_answer
    Heat of combustion of\[C\]and\[CO\]are -394 and -285 kJ respectively, so heat of formation of \[CO\]in kJ/mol is

    A)  -218                                     

    B)  -109

    C)  +109                                    

    D)  +218

    Correct Answer: B

    Solution :

                     \[C(s)+\frac{1}{2}{{O}_{2}}(g)\xrightarrow{{}}CO(g)\] \[\Delta H-[{{\Delta }_{c}}H\,of\,CO-{{\Delta }_{c}}H\,of\,C]\] \[=-[-285-(394)]\text{ }kJ\] \[=-109kJ\]


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