A) \[2\times {{10}^{5}}N\]
B) \[1\times {{10}^{5}}N\]
C) \[8\times {{10}^{5}}N\]
D) \[0.5\times {{10}^{5}}N\]
Correct Answer: C
Solution :
Breaking force\[\propto \]area of cross-section of wire. \[\Rightarrow \]\[F\propto {{r}^{2}}\] \[\Rightarrow \]\[\frac{{{F}_{2}}}{{{F}_{1}}}={{\left( \frac{{{r}_{2}}}{{{r}_{1}}} \right)}^{2}}={{\left( \frac{4}{2} \right)}^{2}}=4\] \[\therefore \] \[{{F}_{2}}=4\times {{F}_{1}}=4\times 2\times {{10}^{5}}\] \[\Rightarrow \] \[{{F}_{2}}=8\times {{10}^{5}}N\]
You need to login to perform this action.
You will be redirected in
3 sec
