A) \[3\times {{10}^{-4}}J\]
B) \[6\times {{10}^{-4}}J\]
C) \[9\times {{10}^{-4}}J\]
D) \[12\times {{10}^{-4}}J\]
Correct Answer: C
Solution :
\[\Delta U={{U}_{2}}-{{U}_{1}}=\frac{1}{2}CV_{2}^{2}-\frac{1}{2}CV_{1}^{2}\] \[\Delta U=\frac{1}{2}C(V_{2}^{2}-V_{1}^{2})\] \[\therefore \] \[\Delta U=\frac{1}{2}\times 6\times {{10}^{-6}}[{{(20)}^{2}}-{{(10)}^{2}}]\] \[\Delta U=\frac{1}{2}\times 6\times {{10}^{-6}}[400-100]\] \[\Delta U=\frac{1}{2}\times 6\times {{10}^{-6}}\times 300=9\times {{10}^{-4}}J\]
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