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MGIMS WARDHA MGIMS WARDHA Solved Paper-2009

  • question_answer
    The moment of inertia of a thin spherical shell of mass M and radius R about a diameter is  \[\frac{2}{3}\]MR 2Its radius of gyration K about a tangent  will be

    A)  \[\sqrt{\frac{2}{3}}R\]                                  

    B)  \[\frac{2}{3}R\]

    C) \[\frac{5}{3}R\]                                             

    D)  \[\sqrt{\frac{5}{3}}R\]

    Correct Answer: D

    Solution :

                     Moment of inertia of shell about a tangent \[I={{I}_{G}}+M{{R}^{2}}\] \[I=\frac{2}{3}M{{R}^{2}}+M{{R}^{2}}=\frac{5}{3}M{{R}^{2}}\] \[\therefore \]  \[M{{K}^{2}}=\frac{5}{3}M{{R}^{2}}\]                 \[K=\sqrt{\frac{5}{3}}R\]


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