A) \[4000{AA}\]
B) \[5000{AA}\]
C) \[6000{AA}\]
D) \[7200{AA}\]
Correct Answer: A
Solution :
The position of maxima \[{{y}_{n}}=\frac{nD\lambda }{d}\] \[\Rightarrow \] \[\lambda =\frac{{{y}_{n}}d}{nD}\] Here, \[n=3,{{y}_{n}}=1.2mm=1.2\times {{10}^{-3}}m,\] \[D=1\text{ }m,\text{ }d=1\text{ }mm=1\times {{10}^{-3}}m\] \[\therefore \] \[\lambda =\frac{1.2\times {{10}^{-3}}\times 1\times {{10}^{-3}}}{3\times 1}\] \[=0.4\times {{10}^{-6}}m=4\times {{10}^{-7}}m\] \[=4000{AA}\]
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